1. The problem statement, all variables and given/known data α=30° β=45° m=10kg a=0 Tα=unknown Tβ=unknown THE ANSWERS SHOULD BE Ta=72N, Tβ=88N 2. Relevant equations mg=10kg*9.8m/s2=98N ∑Fx=ma(x)=0 ∑Fy=ma(y)=0 A Free Body Diagram would show three forces: 98N facing downwards, Ta facing 30° up and to the left, and Tb facing facing 45° up and to the right. 3. The attempt at a solution I tried to isolate the horizontal and vertical components of the forces with Tαcos30°+Tβcos45°=0→Tαcos30°=-Tβcos45° Tαsin30°+Tβsin45°-98N=0→Tαsin30°+Tβsin45°=98N I then tried to solve for T with Tα=-Tβcos45°/cos30° And substitute that into the vertical component equation (-Tβcos45°/cos30°)sin30°+Tβsin45°=98N But I seem to be walking in circles when I attempt to go any further.