Recent content by Anmoldeep
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High School Ion Trap and Time-Varying Potentials
I forgot to write that the answer at the back says something completely otherwise (its only an answer and not a solution) \sqrt{\ \frac{\ \nu _{o}^{2}}{2} +\sqrt{\left(\frac{\ \nu _{o}^{2}}{2}\right)^{2} +\frac{q^{2} \nu _{o}^{2}}{4\pi ^{2} d^{2} mC}}}- Anmoldeep
- Post #2
- Forum: Electromagnetism
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High School Ion Trap and Time-Varying Potentials
Ion traps are very complex, but one of my Physics Olympiad textbooks (this is not homework) presents a simplified model of a resonating charged particle in an ion trap which according to me is wrong, there is either something missing or something overspecified here. A tuned circuit...- Anmoldeep
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- Ion Potential electric energy Potentials
- Replies: 1
- Forum: Electromagnetism
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Time dependant Potential Energy in ion trap
I forgot to write that the answer at the back says something completely otherwise (its only an answer and not a solution) $$\sqrt{\ \frac{\ \nu _{o}^{2}}{2} +\sqrt{\left(\frac{\ \nu _{o}^{2}}{2}\right)^{2} +\frac{q^{2} \nu _{o}^{2}}{4\pi ^{2} d^{2} mC}}}$$- Anmoldeep
- Post #2
- Forum: Introductory Physics Homework Help
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Time dependant Potential Energy in ion trap
Ion traps are very complex, but one of my Physics Olympiad textbooks presents a simplified model of a resonating charged particle in an ion trap A tuned circuit consists of an inductor and a parallel plate capacitor (capacitance C and plate separation d). It has a resonating frequency ##\nu...- Anmoldeep
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- Energy Ion Potential Potential energy Time
- Replies: 1
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
Thanks, sir, I will give it a try and try to approach the same solution the other way. Thanks a lot for your time.:smile:- Anmoldeep
- Post #14
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
So explicitly placing, my question is how to relate the generalised version of density and velocity profiles- Anmoldeep
- Post #12
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
Yes, sir, I understand that. However, I no longer want to use shell theorem, I want to mathematically conclude that any density/velocity profile of the cloud normalized to given conditions will end up in the same max radius, not relying on the force equations at the edge, hence I need a way to...- Anmoldeep
- Post #11
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
Yes sir. I got it that way, I was just unsure of how to proceed with a general density profile.- Anmoldeep
- Post #9
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
Yes- Anmoldeep
- Post #7
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
Sorry for the continuous editing, I have refined the last post and corrected a minor error in the last integral- Anmoldeep
- Post #5
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
@jbriggs444 Thanks for the answer. Yeah, that seems understandable. So no compulsion in assuming that. That aside, I tried my best to solve this using a general radial density variation rho(r) which is, let's say, dependent on the maximum radius of the cloud at any moment. The density profile...- Anmoldeep
- Post #4
- Forum: Introductory Physics Homework Help
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Expanding explosion from an Asteroid
An asteroid of mass M explodes into a spherical homogenous cloud in free space. Due to energy received by the explosion, the cloud expands and the expansion is spherically symmetric. At an instant, when the radius of the cloud is R, all of its particles on the surface are observed receding...- Anmoldeep
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- Asteroid Expansion Explosion Gravitation
- Replies: 13
- Forum: Introductory Physics Homework Help
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Undergrad Work Done in Changing Shape of Current Carrying Loop
I think I found the solution, the textbook directly suggested the use of PE=-M.B, however we know that Del(PE)=M.B(1-cos(theta))=PEtheta - PE0 consider two separate loops of magnetic moment M1 and M2 (square and circle respectively) Del(PE1)=M1.B(1-cos(theta))=PEtheta - PE0 and...- Anmoldeep
- Post #4
- Forum: Electromagnetism
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Undergrad Work Done in Changing Shape of Current Carrying Loop
Thanks for that, although I wanted a deeper explanation as to why potential energy is still defined by the same way, P=M.B is found by integrating Torque =MxB w.r.t (theta), here though theta remains the same and M is changing, I have found an integral by mapping every elemental length on the...- Anmoldeep
- Post #3
- Forum: Electromagnetism
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Undergrad Work Done in Changing Shape of Current Carrying Loop
How would you go about calculating the work done in morphing a square current-carrying loop into a circular current-carrying loop, without change in length while maintaining the same angular orientation with an external magnetic field. My book suggests defining P(potential energy) = M.B (dot...- Anmoldeep
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- Current Loop Magnetic energy Magnetic moment Magnetism Potential energy Shape Work Work done
- Replies: 5
- Forum: Electromagnetism