Recent content by annedi

oh yeah. i just realized that just now.. THANKS AGAIN :)

there is no more information stated here.. thanks for the help stockzahn. I really appreciated it. this was due today

the heat flux from copper to water is 2548.23 W/m^2 at 250C.. is this what you mean..

I'm sorry, I forgot to convert the temperature what i meant by W (area)/ m^2 whatever the area is, you'll plug it in the equation.. so W (x)m^2/m^2 will cancel out thus leaving W as the unit

is this correct. i computed the Hr as a function of area 132.89 W Area /m^2 70543 W Area/m^2

The answer must be in joules per second

I searched it. it says that it ranges from 0.969 - 0.997

Homework Statement Consider a snow-covered surface. Assume that the amount of solar radiation that reaches the top of the atmosphere is 1367 Wm-2. Given that 50% of this solar radiation is either absorbed in the atmosphere or reflected by clouds before reaching the the snow covered surface...

Homework Statement How much heat is radiated in water per sq cm, from a block of copper at 250 C and 1200 . Homework Equations e= 0.6 Hr= (Area)(e)(5.67x10^-8 W/m^2K^4)(temperature)^4 The Attempt at a Solution i'm sorry, i don't know how to solve this one...

oh yeah.. i get it now.. i was a little confused with the formula a while ago.. THANKS A LOT FOR THE HELP ;)

please help :( I know the formula, but i don't understand the question1. Homework Statement a 200g calorimeter, with heat capacity = 0.10 cal/g C, contains 300g of water. a 500 g aluminum shot, at 99 Celsius, was poured in the calorimeter. What would be the initial temperature of water in order...

would this mean.. vf=(5.0m/Time) a=(5.0m / time^2) m= F/a m=40N time^2/5.0m is this right??

Yes, I have. these are the exact words on the book

I don't know if this would really help but I'm dealing here "Newton's 2nd Law of Motion" so the formula here is F=ma..

Yes, I have.. These are the exact words written in the book