Recent content by anooja559

Dear Willem, That is great, Thanks a lot, Could you please elaborate on how to get this

Hi WWGD, Thank you so much. So I integrated the equation ∫(∂M/r∂r+∂2M/∂r2 )= ∫A ----(1) ie ∫∂M/r∂r+∫∂2M/∂r2 = ∫A 1/r*M-∫-1/r2*M + ∂M/∂r = A*r+C1 (integral by parts) 2*M/r+∂M/∂r = A*r+C1 ----(2) Integrating eq(2) again ∫2*M/r+∂M/∂r = ∫A*r+C1 Which gives, 2*M*ln(r)+M = A*r2+C1*r+C2...

Hi, Could you please help me to solve a second-order differential equation given below ∂M/r∂r+∂2M/∂r2 = A [Moderator's note: Moved from a technical forum and thus no template.]