Recent content by antienor
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Undergrad How do you reverse this equation
From the equation below, how do we get the X,Y,Z if the only numbers given are the L,M,N (0.5839, 0.1682, 0.2477)? Thank you! X = 1.57 Y = 5.45 Z = 3.70 T = (1/X+1/Y+1/Z)*100 = 109.0699 A = (1/ (X*T))*100 = 0.5839 B = (1/ (Y*T))*100 = 0.1682 C = (1/ (Z*T))*100 = 0.2477 L = 0.5839 M =...- antienor
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- Replies: 1
- Forum: General Math
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Undergrad Solve for XYZ Given LMN: 0.5839, 0.1682, 0.2477
I see, my bad! L doesn't represent any numbers from the equation and that's not multiplication. I just put L so that I can tell people that I need to get the XYZ from those numbers 0.5839, 0.1682, 0.2477, LMN are just labels for these numbers. No other significant role in the equation. Sorry...- antienor
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- Forum: General Math
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Undergrad Solve for XYZ Given LMN: 0.5839, 0.1682, 0.2477
LMN is just like XYZ variables.- antienor
- Post #5
- Forum: General Math
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Undergrad Solve for XYZ Given LMN: 0.5839, 0.1682, 0.2477
Hi already edited my post. This clears everything? Thanks!- antienor
- Post #3
- Forum: General Math
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Undergrad Solve for XYZ Given LMN: 0.5839, 0.1682, 0.2477
From the equation below, how do we get the XYZ if the only numbers given are the LMN (0.5839, 0.1682, 0.2477)? Thank you! X = 1.57 Y = 5.45 Z = 3.70 T = (1/X+1/Y+1/Z)*100 = 109.0699 A = (1/ (X*T))*100 = (L) 0.5839 B = (1/ (Y*T))*100 = (M) 0.1682 C = (1/ (Z*T))*100 = (N)...- antienor
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- Replies: 7
- Forum: General Math