anuttarasammyak's latest activity
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anuttarasammyak replied to the thread J_1(x) = (x^2/10)*(J_1(x) + J_3(x)) How to solve?.This anti-symmetric equation has six non-zero solutions. -
anuttarasammyak reacted to Demystifier's post in the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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Under a coordinate transformation ##x^{\mu}\to x'^{\mu}=f^{\mu}(x)##, the two metrics transform as $$g'^{\alpha\beta}=\frac{\partial... -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Thank you @Demystifier 1. I observe that a. ## \bar{g}_{\mu\nu}-g_{\mu\nu}## transforms as a covariant tensor under coordinate... -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.I should appreciate it if you could teach me how to verify it. -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Thank you, @Demystifier. In general, the difference of two tensors is again a tensor. However, in the context of variations of the... -
anuttarasammyak reacted to Demystifier's post in the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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I believe there is no such quantity, because you study a variation of the object that defines the covariant and contravariant components. -
anuttarasammyak replied to the thread J_1(x) = (x^2/10)*(J_1(x) + J_3(x)) How to solve?.You forgot to put double dollar signs at head and tail of the equalion lines. I put them. ------------ Has any one any idea to solve... -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.It is a tensor whose covariant and contravariant components are ##\delta g_{\mu\nu}## and ##-\delta g^{\mu\nu}##, respectively... -
anuttarasammyak reacted to Demystifier's post in the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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3. is just a definition of the dual tensor, i.e. the rule how to raise indices in the same world. In 2. you try to compare quantities... -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.1. We can derive the equation $$ \delta g^{\mu\nu}=-g^{\mu\alpha}g^{\nu\beta}\delta g_{\alpha\beta} $$ by indeces up down operation... -
anuttarasammyak reacted to Demystifier's post in the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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Yes, I think that's right. But the first convention is not completely arbitrary. In a sense ##g_{\mu\nu}## is more elementary than... -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Now I know that $$ (\delta g)^{\mu\nu}=g^{\mu\alpha}g^{\nu\beta}(\delta g)_{\alpha\beta} $$ $$ \delta... -
anuttarasammyak reacted to Demystifier's post in the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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@anuttarasammyak in general ##\delta \overline{T} \neq \overline{\delta T}##. (By the way, in LaTeX use the command \overline, not \bar... -
anuttarasammyak replied to the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.@PAllen @Demystifier Thanks. I went a bit easy on T . -
anuttarasammyak reacted to PAllen's post in the thread Graduate Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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I don’t see why you would expect that last to be true in general. Starting from T with indexes down, in one case you have the metric...
