anuttarasammyak's latest activity

Quantum field theory treats the decoherence between the system and the measuring apparatus, but does it not fail to account for the...

You are conflating a bunch of different things here. Much of what you mention above (probability as squared amplitudes, role of...

This is my conjecture about QFT that I learned from this thread and some othre readngs: In quantum field theory (QFT), measurement is...

Am I correct in understanding that both ⟨v⟩ = ⟨p⟩/m and ⟨v⟩ = d⟨x⟩/dt are valid in the non-relativistic regime for a free particle?　 If...

No position means no path along which we can integrate to find the proper time. Instead we use QFT and calculate an amplitude for a...

I have read that in relativistic quantum theory the decay rate is computed from the weak-interaction matrix element using the...

Thank you. Re:#30 Can we call ##\frac{<p>}{m}##, relativistically ##<\frac{pc^2}{E}>, ## as well as ##\frac{d}{dt}<x>(t)## the...

So even in free space QM tells us nothing about velocity ?

Cosmic-ray muons correspond to wave packets in free space, and their lifetime extension can be explained by the Lorentz factor. Muons in...

For a wave packet in free space, the state is a superposition of plane waves with different momenta. Each momentum component behaves as...

If it is a wave packet in free space, it has a velocity corresponding to each momentum component. One may regard it as a kind of...

OK, it seems clear that viewing a particle in a stationary state as moving with average speed ##\sqrt{⟨\mathbf{V\cdot V}⟩}## is an...

The decay law $$N=N_0e^{-\lambda t}$$ seems to require rest frame of the particle(s) where ##\lambda## be measured and ##t=\tau##...

As s=s', s is invariant between IFRs, not its time component quantity you refer.

I have read that muon could be captured by nucleus which shortens its life time. This model seems not appropriate to investigate the...