Recent content by apekattenico

Fair point, but I think you are over complicating things. And I did so on purpose. I might be in the wrong here, but allow me to explain how I think, and feel free to correct me. The difference in pressure causes a net force, which drives the air forward. Given a pressure...

\int\int\frac{df}{dx}\frac{df}{dy}dydx Keep in mind that we do not apply the same concept as we do indefinite integral, the integral has to be bounded by a plane (may it be 2,3, or more)

I don't see why not. What do you do to find the original function for a single variable function?

At what speed (flow/volume for that matter) does air leave an outlet when you know it holds x bars in the pipe? (It goes from x to zero (or athmospheric) -- you know the pressure difference) I assume you can neglect relative roughness, resistance, and so on as the pressure drop is over...

Excellent answer! I guess I could've phrased my question a little better. At what speed does the air leave the outlet when you know it holds 7 bars in the pipe? Thanks a lot for the quick response :) (Anyone know a page where I can find general forumlas regarding compressed air?)...

Hi, I want to know how high the flow rate trough a pipe is (outlet), but I only now the pressure difference (0.7MPa or 7 bar), and the diameter of the pipe. At what speed (or for that matter volume) does air leave a pipe when the pressure difference is 7 bar, and the diameter is 25.4mm...