Recent content by APett

Yes, I understand that the car dist is bike dist + 80 because it's starting out 80 meters ahead, but I don't understand how that can help me find where the bike overtakes the car. The overtake point will be at a distance driven by the bike, which will be the same as the distance driven by the...

SteamKing: I guess I should've mentioned that I've thought about distance, and that I don't know how to find where they meet either. jedishrfu: By plug in, do you mean into the second equation I listed? I've thought about this for a good while now, and I just can't figure out how to apply the...

Homework Statement A motorbike is driving at a constant velocity of 25m/s, and 80 meters in front of it, a car is accelerating from standing still, with a constant acceleration of 3m/s2. When will the bike overtake the car? Homework Equations s=vt Possibly s=ut+0.5at2 The Attempt at a...

Say we have two cars, Car A and Car B. Car A is 25 meters ahead and has a constant velocity. Car B has the exact same velocity at the moment of observation, but also has a constant positive acceleration. If I want to calculate how long it takes for Car B to overtake Car A, wouldn't it be the...

Sorry, I just realized it's probably the wrong subforum. Can someone move it?

Say we have two cars, Car A and Car B. Car A is 25 meters ahead and has a constant velocity. Car B has the exact same velocity at this moment, but also has a constant positive acceleration. If I want to calculate how long it takes for Car B to overtake Car A, wouldn't it be the same as...