Recent content by ArcadeEdge

Thank you!

I think I got it now. If looking straight down on the xy-plane you get a straight line with a slope of 2. The equation of the straight line is 2x-y=12 which is also the equation of the plane. And for question 2, I got the vector function to be r(t) = <t, 2t-12, 5t2 - 48t + 144>

I need a vertical plane, so I'm trying to find a plane normal to, for example, z=1 right?

And for question two, I plugged in y = 2x+2 into f(x,y). so f(x,y)=z=5x2 + 8x + 4 and y = 2x+2. So my vector function is <x, 2x+2, 5x2+8x+4> can it also be written r(t) = <t, 2t+2, 5t2+8t+4> ?

Oh, I see. I was drawing the vector from the origin so I couldn't see how the point and the vector touched. I take the cross product of <2,4,0> and <0,0,1> and get 4i - 2j to be a vector that is perpendicular. And then to find the equation of this plane I can use the equation I had above. I...

okay, so the point would then be (9,6,0). But where do I go from there?

Homework Statement f(x,y) = x2 + y2 P(9,6) v=<2,4,0> 1)Find a vertical plane that passes through the point P(9,6) and has the vector v=<2,4,0> 2)What is the vector function of the curve of intersection of the vertical plane and z=f(x,y) Homework Equations A(x - x0) + B(y - y0) + C(z - z0)...

You add them together and set them equal to zero and solve for xi and yj right? When I do that I get 0 for both x and y.

This is a problem from my Calculus class in the sections about vectors. Homework Statement Two forces F1 = 2i + 6j and F2 = 2i -2j act on an object. What additional force is needed to keep the object at rest? Homework Equations I'm not sure where to start. The Attempt at a...