1. The problem statement, all variables and given/known data f(x,y) = x2 + y2 P(9,6) v=<2,4,0> 1)Find a vertical plane that passes through the point P(9,6) and has the vector v=<2,4,0> 2)What is the vector function of the curve of intersection of the vertical plane and z=f(x,y) 2. Relevant equations A(x - x0) + B(y - y0) + C(z - z0) normal vector n= <0,0,1> given point and vector: P(9,6) v = < 2, 4 0> 3. The attempt at a solution I tried plugging the give point and and the normal vector into A(x - x0) + B(y - y0) + C(z - z0) and I got 3x+2y but that's not a vertical plane. I also tried plugging in the point and the given vector and got x+2y-21 and that doesn't look right either. I found the unit vector to be <1/√3 , 2/√3 , 0>. I'm not sure if I need to use that find the vertical plane.