Recent content by aready
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Lagrangian invariant but Action is gauge invariant
Well, I can see how Fλ ϵλμν∂μ ∂ν Λ would vanish. The \mu and \nu are symmetric wrt to exchange for the partial derivatives, but the indices of the \epsilon symbol are totally antisymmetric. Multiplying a symmetric tensor and an antisymmetry one gives zero always.- aready
- Post #2
- Forum: Advanced Physics Homework Help