Recent content by Arno@praxispc

ok so what you are saying is that if i use ohms law V=I*R I will have to use the 8 ohm resistor times by the current of 2.142= 17.136V Is this the voltage after it went through the resistor or is this the amount of voltage drop?

Homework Statement The circuit has a battery Voltage of 30V, a resistor of R1(8ohms), R2 (2Ohms) and R3 (4ohms) in series. Calculate the voltage drop over R1 Homework Equations Please give me the proper equation of this? The one I've got says you take 30-8I-2I-4I=0 which gives you...