Recent content by artoribio

Maybe it was parallel to the surface? I think that E_phi just ends up becoming E_perpendicular(to the surface) because the lateral portions cancel, no?

I think that I understand your explanations. As for the symmetry of the cylinder or in general if the field lines are perpendicular to the surface then you can take the E values. So in this case E_z = 0 because it is parallel to the charge. That is what I gathered from a Khan Academy video. As...

I was thinking in terms of two positive nodes. Is that wrong? In the case of a positive and negative set it would just be straight lines between the center and and the shell considering, right?

I thought that the area would not have a zero E-field outside of the coaxial cylinder. I did not put an |⃗E| equation for b<r so I'm am not quite sure what you are referring to. As for your quoted portion, I was thinking that directly in between a and b the fields from the solid center and the...

Homework Statement I have posted the given question and conditions in the attached image Homework Equations (Q_enclosed/ epsilon_0) = closed integral (E-field) dA Q_encolsed = p*A V(r)= -Int_(from origin to r) (E-field(r'))*dl' The Attempt at a Solution [/B] a) E=0------>For r<a...