Recent content by artsakh

im not sure. i don't see how its related at all, i mean besides a volume-density relation

well i have the equation E = 2kλ/r. E = k8nC/(.08)2?? but how does that help??

The charge outside the sphere doesn't affect the flux, correct? when adding the charges inside the sphere, -2 and 8, which gives 6nC, and putting it through the formula, 4πkQin, i get 678.58, but the correct answer is 886Nm2/C

Homework Statement The y-axis carries a uniform linear charge density of -2 nC/m, and there is a 8 nC point charge at the point (3 cm, 0 cm, 0 cm) as well as a -4 nC point charge at the point (-8 cm, 0 cm, 0 cm). What is the electric flux through a closed spherical surface of radius 4 cm...

You're right but you have to divide that number in half

Thank you very much but we already figured this one out, its the other two that i need help with

Thank you very much! Trying to get all this in before my final tomorrow, thanks a lot.

A 4 kg mass is attached to a 100 N/m spring and oscillates with an amplitude of 0.75 m across a horizontal frictionless surface. When the kinetic energy is 70% of the total mechanical energy, by how much is the spring stretched or compressed? I'm not sure how to approach this problem. I could...

Well L=r\timesp=I\omega, so the L of the feeder is 0.12*0.6? I don't understand what you mean by the bird adding its rotational momentum. The momentum of the bird is .150*1.5 tangent and opposite to the rotation of the feeder isn't it? You can get the \omega of the bird but i don't see how that...

Not really, I am sorry for being such a pain though :shy: The weight of the feeder can be calculated because r and I are known, and it is 6kg, the \omega of the bird comes out to be -7.5 (but what are the units? seconds?) i don't really see where to go from here...

yea, the problem was with the I, the correct answer is 2.63

1 mile = 1.609 km = 1609 meters, 1 hour = 3600 seconds. so 60*1609 divided by 3600 gives you m/s which equals 26.81667 m/s

There's many, here is the formula sheet we are provided with: http://i52.tinypic.com/5k34ic.jpg

yea it is

I have the formula I_{disk}=1/2MR^2, and T=I\alpha, and also a_{r}=\omega^2r that'll give me the I and the rotational acceleration? i still don't know what to do after though...