I found the answers to each part but part C. The formula from shooting star is how I found part A. So why would you not add the velocities of the insect relative to the water and divide by 2 in order to find the average velocity of the bug relative to the water for part c?
I thought in order to solve part C. I had to do this:
square root of (.510/.770)^2 + (.540)^2 then divide that answer by 2 to find the average. What did I do wrong?
I don't know how to solve b and c. I don't even know where to start. can anyone point me in the right direction? a formula or some way to think of it other then the way the question states it. I figured out A finally but I never know what equation to use.
So to fine the time it takes the boat to go 400 meters at a speed of 9 m/s. I divided 400/9.0 and got 44.4444s.
Then I thought to find the downstream displacement given that time you would just divide the 44.444s/(1.8m/s)? But that's wrong and I don't know what else to do?
[SOLVED] How far downstream has the boat moved?
I can't figure out the last part of this question. It's probably very simple and I'm just over looking it. The answers in part A are right. I just don't know how to get part B.
A river flows due east at 1.80 m/s. A boat crosses the river from...
I've been having difficulty with this problem and can't seem to find where to start. Any help would really be appreciated.
A water insect maintains an average position on the surface of a stream by darting upstream (against the current) then drifting downstream (with the current) to its...