For some reason i don't know why i can't get this problem:
A stunt driver travels a total distance of 1172 ft moving at a constant speed of 40 mph while weaving through an obstacl ecourse. If the total displacement of the car is 600 ft from the start of the course to the finish, determine...
i think i solved the second part but tell me if this makes sense at all!
the temp rises to 85C (359.15 K) and tire increases volume by 2%
so using the numbers from part A with the same equation
400/313.15=P/358.15
solve for P=457.726 BUT it's saying the volume of the tire increased by...
ok i got the first part
a)
Pinitial/T initial=Pfinal/Tfinal
normal pressure= 1atm= 101.325kPa
convert temps into Kelvins
T initial= 283.15
Tfinal= 313.15
SO...
101.325/283.15=P(.28)/313.15
P= 400kPa
but now i don't know how to get the second one
I know the answer for b...
here's another one that stumped me
An automobile tire is inflated with air originally at 10C and normal atmospheric pressure. During the process the air is compressed to 28% of its original volume and the temperature is increased to 40C.
a) what is the tire pressure?
b) after the car is...
like i said.. i didnt know where to put this question... i saw clac and beyond and figured it would be a good place to put it...so my apologies..
i figured out the problem last night right after i posted it!
F/A=Y*coefficient of linear expansion*change in temp and solved for temp...
Thermal Expansion Problem
i posted this thread in another forum because i really don't know where this question would apply but here goes
i've been working on this problem forever and i don't know what I'm doing wrong!
a steel rod undergoes a stretching force of 500 N. Its cross sectional...
Thermal Expansion Problem
i've been working on this problem forever and i don't know what I'm doing wrong!
a steel rod undergoes a stretching force of 500 N. Its cross sectional area is 2.00 cm^2. Find the change in temperature that would elongate the rod by the same amount as the 500-N force...