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My working now: sin3x+sinx = 2sin(3x+x/2)cos(3x+x/2)=0, 2sin2x.cos2x=0 adding into parenthesis 1/2(2sin2x.cos2x)=sin2x 2sin2x.cos2x=2sin2x 2sin2x.cos2x - 2sin2x=0 2sin2x(cos2x-1)=0 2sin2x=0, cos2x=0 But using the general equation formula for cos2x=0 gives me x=∏n, when the...

Ah, yes it is, sorry. And thanks, I'll see what else I can do.

Hello! I've been tackling the question 'Express sin3x+sinx as a product and hence solve 1/2(sin3x+sinx)=sin2x ; x∈R' but I'm stumped - I'm not sure whether I've even approached it correctly. This is what I did: sin(3x+x)=sin3x.cosx+sinx.cos3x inserting this into the second equation...