Recent content by aurellinlmnsc

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    Inverse of (2x^2+x+1)/(2x^2+x-1)

    when I check in wolframalpha if the function x = -1/4 ± √[1/(y - 1) + 9/16] is the same as 1/4(-1 +/- sqrt(1+8 ((y+1)/(y-1))) it doesn't even confirm but confused it as an entirely new function...
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    Inverse of (2x^2+x+1)/(2x^2+x-1)

    (2x - 1)(x + 1)y - 2 = (2x - 1)(x + 1) (2x - 1)(x + 1) does NOT = (2x^2 + x +1)
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    Inverse of (2x^2+x+1)/(2x^2+x-1)

    Yes, I am sure. This problem comes from the Chemistry Maths Book, by Erich Steiner. Exercise Section 2.5 problem 44. The answer is in the back of the book, but I don't even know how in the world they got to that answer as well. I've been running smoothly through the first 43 problems just...
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    Inverse of (2x^2+x+1)/(2x^2+x-1)

    Homework Statement Find x as a function of y, if y = (2x^2+x+1)/(2x^2+x-1) Homework Equations (1/8 (-4 i x+sqrt(7)-i) (4 i x+sqrt(7)+i) ) / (x+1) (2 x-1) for 2x^2+x+1, how do I factor that out to get 1/8 (-4 i x+sqrt(7)-i) (4 i x+sqrt(7)+i)? quad. formula? The Attempt at a...