Recent content by avelon

When an object is placed at the focal point, the image will be at inf :-) For lens1: focal = 50 mm Object_distance = 50 mm Image_distance = inf (this will be object for the second lins) Magnification = (inf/50) For lens2: focal = 400 mm Object_distance = inf Image_distance = 400...

hmmm..Lens equation for lens1 would giva us 1/object_distance + 1/image_distance = 1/focal "assuming it's a virtuall image", otherwise image_distance would be inf for lens 1 1/(-50)+1/i_d = 1/50 image_distance = 25 Magnification (lens1) = 25/50 = 1/5 Magnification (lens2) = 400/600 = 2/3...

This is what I did Magnification M = image_distance S / object_distance S' M = 400 / 600 = 2/3 I don't think this is the right solution... any comments? :--)

Homework Statement A light source placed in the focus of a (thin) lens with a focal length of 50mm. A second (thin) lens (with focal length = 400mm) was placed 600mm after the focal point of the first one, an image of the light source was captured at the seonds lens focal point. How...