Recent content by azsx11

Sorry, I'm none the wiser. Was my calculation up to that point correct?

This is what I've tried to do. 900000/2 - half of the object is submerged. = 450000 Kg displaced 450000*10 = 4500000 N upthrust. (I'm not sure if that's correct) If it sinks the weight of the displaced liquid is equal to the objects weight. = 900000 Kg 900000*10 = 9000000 N...

Sorry, I got my order wrong. d = 30 g/cm3 = 30000 Kg/m3 30000 = m/30 m= 900000 Kg etc... Is this the right way to approach the question?

Calculating upthrust on an object Homework Statement An object made entirely of one material has a volume of 30m3. It floats in a liquid of density 30 g/cm3 with only half it's mass below the liquids surface. The object is then placed in a liquid of the same volume but with a density of 1...