Calculating upthrust on a solid object

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Homework Help Overview

The problem involves calculating the upthrust on a solid object that floats in two different liquids with varying densities. The object has a specified volume and the scenario explores the relationship between the object's weight and the weight of the displaced liquid.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations related to the mass and weight of the object in different liquids, questioning the method of determining the mass from density and volume. There are inquiries about the conditions under which the object floats or sinks in the second liquid.

Discussion Status

Some participants have provided calculations and reasoning regarding the upthrust in both liquids, while others are questioning the validity of these approaches. There is an ongoing exploration of the principles of buoyancy and the implications of the object's behavior in different liquid densities.

Contextual Notes

Participants are working under the assumption that the object is made of a single material and are considering the effects of different liquid densities on buoyancy. There is some confusion regarding the calculations and the definitions of weight and upthrust in the context of floating and sinking.

azsx11
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Calculating upthrust on an object

Homework Statement



An object made entirely of one material has a volume of 30m3. It floats in a liquid of density 30 g/cm3 with only half it's mass below the liquids surface. The object is then placed in a liquid of the same volume but with a density of 1 g/cm3. If the final upthrust that will act on the object is expressed in the form a*10bN give the values of a and b. Assume g to be 10 ms2

Homework Equations



d=m/v

The Attempt at a Solution



1st liquid

3000=m/30
=90000
90000/2 = 45000 Kg displaced

45000 * 10 = 450000 N upthrust (archimedes)
45000/3 = 15000 N upthrust in 2nd liquid

a=1.5, b=4

I honestly have no idea really.
 
Last edited:
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Hi azsx11, welcome to pF.
How did you get
3000 = m/30?
 
rl.bhat said:
Hi azsx11, welcome to pF.
How did you get
3000 = m/30?

Sorry, I got my order wrong.

d = 30 g/cm3 = 30000 Kg/m3

30000 = m/30

m= 900000 Kg

etc...

Is this the right way to approach the question?
 
When the body is floating, weight of the body is equal to the weight of the displaced liquid.
So what is the weight of the object?
In the second liquid whether the object sinks or floats?
If it sinks, what is the weight of the displaced liquid?
 
rl.bhat said:
When the body is floating, weight of the body is equal to the weight of the displaced liquid.
So what is the weight of the object?
In the second liquid whether the object sinks or floats?
If it sinks, what is the weight of the displaced liquid?

This is what I've tried to do.

900000/2 - half of the object is submerged.

= 450000 Kg displaced

450000*10 = 4500000 N upthrust.

(I'm not sure if that's correct)

If it sinks the weight of the displaced liquid is equal to the objects weight.

= 900000 Kg

900000*10 = 9000000 N

Am I on the right track?
 
If it sinks the weight of the displaced liquid is equal to the objects weight.
It is no true.

If it sinks the weight of the displaced liquid is equal to the loss of objects weight.
 
rl.bhat said:
If it sinks the weight of the displaced liquid is equal to the objects weight.
It is no true.

If it sinks the weight of the displaced liquid is equal to the loss of objects weight.

Sorry, I'm none the wiser.

Was my calculation up to that point correct?
 
In the second case, volume of the displaced liquid is...?
What is the density of the water?
What is the mass of the water and its weight?
Hence what is the upthrust?
 

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