Recent content by b3nji3

yeah i really can't remember how to use this method... which is embarrassing id say I am pretty screwed really i have no idea how id adapt that to what i have. thanks anyways tho

yeah but the polar for this is just overcomplicating things (im just not good at it) but i can't remember the calcultion method...

hi i know how to add 90degree phase shifts but i can't remember how to add two simple waveforms... i need to express v1 + v2 if; v1 = 96sin(120\Pit+ \pi/6) v2 = 90sin(120\Pit-\pi/3) can anyone help please!?

actually it has to be right... it works out at 7.5ms and at 50Hz a wavelength is 1/50 hence 20ms so if that is 2\Pi then it would be lagging at \Pi/4 so that's 0.0025 cause its half of the 5ms or \Pi/2 for the original peak so its 5ms plus 2.5 ms or technically \Pi/4 + \Pi/2 or 3quarters \Pi...

i missed the = t bit on the end lol

lmao! yeah my girl friend's fine lol she has some books on latex and a cd but I am not it the know bout that stuff i don't think its the same as the latex stuff on here :wink:. 82sin(100pi*.05-pi/4) is what i just typed into goolge and it gave me the answer with its built in calc lmao! i...

but again that's ace :P cheers

you're good! lol but yeah that makes sense duh to me lol I am mech elec so sometimes things from one help in others after all the maths is always the same just with different letters its just a language tool as i see it and I am interested in it but not so good at it. sometimes helps my gf...

yeah tell me about it lol but yeah cheers still~! got to work on the forces bit now with the angle i get then move to the next questions. got more difficulties to come lol in the form of adding waves etc and trig identities and working them thru in my head and showing i can do it. oh by the...

so you're only new to this place yourself then? (420 posts)?

yeah i figured it in the end but you helped so much nice one! now i have to do the hard it with summation of forces etc once i get the angles :smile: hope I'm better at that despite never being taught it lol

Hi that's a massive step lol was so stuck but i thought that on the fisrt triangle the pythagorus would be L^2 = BD^2 + 17.3^2 hence BD^2 = L^2 - 17.3 and BD^2 = L^2 - 22.7 is that correct? :S because th earea on the hyp is the sum of the areas on the other two sides a^2 + b^2 = c^2 with c as...

i meant you're not fully understanding m8 OR I'm not understanding still lol

hey Thanks for the reply but I don't think you've fully understood I'm not understanding you lol. I didn't explain it well I'm sorry but i keep ending up with too many unknowns, because if i split it into two triangles like i was working on originally then it gives me two unknowns in...

Hi, I'm really stuck on this question... "A truck dealer wants to suspend a 2.5 tonne truck as shown for advertising. the distance b (which is 17.3m) shows a horizontal distance of the suspension point B from the anchor point A. The sum of the lengths of cables AB and BC is 42m. calculate...