Recent content by bad poster

Remove "finite" from problem two and figure out a set and operation that satisfies the property given, but which is not a group. (hint: ). Why does the condition given in the first problem eliminate the problem that arises? This should help you understand the reason why the conditions are...

As a hint, note that (bab^{-1})^2 = (bab^{-1})(bab) = ba(b^{-1}b)ab^{-1} = baeab^{-1} = baab^{-1} = ba^2b^{-1}, where e is the identity in G.