Recent content by BAJ

Sorry to reply late. Was very busy since Tuesday. When I connected the multimeter to take readings (1 end to cathode and other end to anode), it showed around 400mV max and 2mA max. I didnt measure by connecting both anode ends. And to prevent contamination of electrode, I used graphite. And...

Yes I want to generate power. In fact I want to increase the output. Making a line of chemical cells to add up voltages is not feasible. Thought of that first but how many will I add up to get to light a LED bulb? Thats why wanted to increase by looping the output and keeping the load in...

Yes that electrode is placed above the circuit. It is also made of graphite powder and separated from the circuit using a cloth, mainly a polyester-cloth like J-cloth. It is also called air-cathode as it is in contact with the air. I also attached a copper wire to it for taking readings. Because...

Ok. Explaining what I have done so far. The components I am calling current sources are commutator carbon brushes, attached to a wire which is attached to the circuit, parallely (as shown in my diagram ... the red part). They are dipped in sewage water where, through microbial respiration all...

Ok sure. Thanks for all of your explanations. It helped to get a clear understanding. "It's the boss when it comes to current !" ------ I will definitely remember this :)

The voltage drop across the current source must be determined by the circuit it is connected to. In my case, it may be ~50mV or something, I forgot actually. And yes I agree to your 2nd sentence too if the resistance in the circuit is considered constant. If the resistance is variable then it...

But as I explained the components I am calling current sources are not conventional current sources, they draw current from an electrolysis of a solution, not from the battery. Or are you saying, if I attach the parallel circuit with battery, these graphites will draw current from the battery...

Thanks for your quick explanation, cleared the matter more. However consider this, the current sources are not drawing current from the battery, they are simply graphite placed parallely like the current sources drawing current from an electrolytic solution. And I have experimented earlier...

And moreover I don't want to consider it as equivalent of 5mA in series with the battery. Because if you consider only the parallel circuit and the current source, then both pts A and B will have 5mA current. Now when battery delivers 50mA current in pt A, then definitely backflow is going to...

"No the current source's value will determine total circuit current is my understanding of this." ----- didn't understand. can u explain a bit??

But won't the resultant current add up although the current source is adding current to the circuit?

55mA. Isn't it?

Actually by adding a battery I meant connecting the battery in a way that it is able to deliver the current to one terminal. However here is my proposed circuit.

Assume I have a parallel circuit of current sources with 5 current sources generating 1mA each. Therefore from both the terminals I will get 5mA total. Now if I add a battery to one of the terminals where current(i) will flow into my circuit. If i = 50mA, will I get 55mA current from another...