Recent content by Ballox

An easy way to remember this (I use this method): Z - "Zame" side E - different sides

Hmmm. So I read through all your responses and would like to thank you all for your help. I looked back at the question and this is my solution: limt->x [csc(t)-csc(x)]/(t-x) = d/dx csc(x) (not sure if this is represented correctly, but I see some sort of relationship here) => f(x)=...

Haven't learned L'hopital's rule yet. I believe we're supposed to use other methods

I don't recognize that as a standard trigonometric identity :(

Homework Statement f(x)= lim t-> x [csc(t)-csc(x)]/(t-x). Find the value of f'(PI/4) Homework Equations I can see that this equation somewhat resembles one of the first principle def'ns lim z->x [f(z)-f(x)]/(z-x) The Attempt at a Solution Not really sure how to begin. I...

Thank you kindly for your help.

Alright, so I just did it again... And in fact I was able to apply that theorem THREE times. My final answer was 1/2\sqrt{2} Would this answer be correct?

Hmm. I do know that. I'll see what I can do. Thanks for the hint.

Homework Statement limx->0+ [tan(\sqrt{x})-sin(\sqrt{x})] / x\sqrt{2x} Homework Equations tanx= sinx/cosx The Attempt at a Solution I set u= \sqrt{x} Therefore as a->0, u->0 And I get the limit =lim x->0+ (tan(\sqrt{x})-sin(\sqrt{x}))/ (x*\sqrt{2}* \sqrt{x}) = 1/\sqrt{2}lim u->0...

Never mind. I've figured out the solution. The force of the locomotive on the first car involves the masses of the 1st and 2nd cars. Therefore I add the two masses together to get the total mass however I keep acceleration the same... Using Newton's second law equation I determine the force. F...

Sweet. Thanks for your help.

Homework Statement A train consisting of two cars pulled by a locomotive experiences an acceleration of 0.33m/s^2 [fwd]. Friction is negligible. Each car has a mass of 3.1 * 10^4 KG. a. ) Determine the force exerted by the first car on the second car. b. ) Determine the force exerted by...

So setting the gravitational force equal to the buoyant force would be: mG = 2.7 * 10^3 N [up] ( I rounded this, it really should be around 2740.5 N) Which we would solve for m as : 279.6 kg. But this gives us the mass when when the gravitational force is equal to the buoyant...

Homework Statement A hot - air balloon experiences an acceleration of 1.10 m/s^2 [down]. The total mass of the balloon, the basket, and the contents of the basket is 315 kg. The balloonist wishes to change the acceleration to zero. There is no fuel left to heat the air in the balloon...