What is the force exerted by the locomotive on the first car?

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Homework Help Overview

The problem involves a train with two cars being pulled by a locomotive, experiencing a specific acceleration. The focus is on determining the forces exerted between the locomotive and the first car, as well as between the two cars, using principles of Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Newton's second law to find the force exerted by the first car on the second car and expresses difficulty in calculating the force exerted by the locomotive on the first car.
  • Some participants suggest using Newton's third law to relate the forces between the cars and the locomotive.
  • One participant notes the importance of considering the total mass of both cars when calculating the force from the locomotive.

Discussion Status

The discussion includes attempts to clarify the relationships between the forces involved. Some guidance has been offered regarding the application of Newton's laws, and there is acknowledgment of the need to consider the combined mass of the cars for the calculations. However, there is no explicit consensus on the final approach to the problem.

Contextual Notes

The problem is constrained by the requirement to apply Newton's laws and the given acceleration, with the assumption that friction is negligible. The original poster's confusion regarding the calculations indicates potential gaps in understanding the application of these principles.

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Homework Statement


A train consisting of two cars pulled by a locomotive experiences an acceleration of 0.33m/s^2 [fwd]. Friction is negligible. Each car has a mass of 3.1 * 10^4 KG.

a. ) Determine the force exerted by the first car on the second car.
b. ) Determine the force exerted by the locomotive on the first car.


Homework Equations


Applying Newtons third law of motion which states:

for every action force, there is a simultaneous force equal in magnitude, but opposite in direction


The Attempt at a Solution



I drew a FBD of the situation and solved for part a) by simply applying Newtons second law equation [ F= mA ]

I solved for F and got 1.0 * 10^4 N.

However I have trouble solving for part b.)
The answer is supposed to be 2.0 * 10^4 N, but I can't get it.


Would appreciate any help/advice!
Many thanks in advance.
 
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Since your answer for part a) is the force of the first car pulling on the second, now you can apply Newton's third law.
 
Never mind. I've figured out the solution. The force of the locomotive on the first car involves the masses of the 1st and 2nd cars. Therefore I add the two masses together to get the total mass however I keep acceleration the same...

Using Newton's second law equation I determine the force.

F = mA
F = (62000)(0.33)
Therefore F = 2.0 * 10^4 N [fwd]
 
Last edited:
Ok. Since car 1 pulls car 2 with such a force you got in part a), car 2 must pull car 1 with an equal and oppose force according to Newton's third law. From there you can calculate the force exerted on car one by the locomotive. Maybe drawing a free body diagram would help.
 

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