Recent content by bambino321

well it should be (24.29+10)/9.8 but I am not getting the concept, I know that 24.29 is the velocity when it hits the ground and 10 is the initial velocity so they have to be positive but I don't know about gravity since gravity is always pull downward so it has to be negative right...? if you...

i have plugged in (24.29-10)/-9.8=-1.45

the first equation v=v0+(-9.8)t solve for t which i have (v-v0)/(-9.8)=t and i got -1.45s which is totally wrong since time can't be negative, I am not surewhere i have done wrong...

i found v^2=10^2+2(-9.8)(-25) did the math and v=24.29m/s when it hits the ground

v^2=v(int)^2+(2)(delta y)...?

1. A ball is thrown vertically upward with an initial speed of 10m/s from thetop of a building, at a height of 25m from the ground. Assume free fall conditions. a. To what maximum height above the ground does the ball rise? b. With what velocity does the ball strike the ground? c. How long...