Recent content by BandGeek13
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Friction Due to Jumping w Parachute
thanks for all of your help everyone!- BandGeek13
- Post #9
- Forum: Introductory Physics Homework Help
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Friction Due to Jumping w Parachute
Do you mean the acceleration of the rock towards the ground? haha. Anyway, I'm confused by what you said when finding two different ways of expressing a. If I use the kinematics equation, I get a=6m/s2 So then, Fg=mg =(.5 kg)(a) =(.5 kg)(6m/s2) =3 N And, F=ma F=(.5 kg)(9.8...- BandGeek13
- Post #6
- Forum: Introductory Physics Homework Help
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Friction Due to Jumping w Parachute
Either F=ma F=(.5 kg)(9.8 m/s2) F=4.9 N Fg=mgh Fg=(.5 kg)(9.8 m/s2)(75 m) Fg=367.5 N Ffriction=Fnet-Fg Ffriction=4.9 N-367.5 N Ffriction=-362.6 N Or \Deltad=v1\Deltat+.5a(\Deltat)2 75 m=0 m/s(5 s)+.5a(5 s)2 a=6m/s2 F=ma F=(.5 kg)(6 m/s2) F=3 N Fg=mgh Fg=(.5 kg)(6...- BandGeek13
- Post #3
- Forum: Introductory Physics Homework Help
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Friction Due to Jumping w Parachute
Homework Statement A 500 g rock falls out of a 75 m tree. It takes it 5s to parachute to the ground. How much friction is upon it?Homework Equations Fnet=ma Fg=mgh possibly \Deltad=v1\Deltat+.5a(\Deltat)2 and other kinematics formulasThe Attempt at a Solution I tried to find the net force...- BandGeek13
- Thread
- Friction Parachute
- Replies: 8
- Forum: Introductory Physics Homework Help
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Understanding the Physics of Music: Frequencies, Overtones, and Resonance
okay, well it says this in my textbook and we've done classwork using these, but maybe it's just a way of explaining easier? i'm having trouble visualizing this... thank you so much for all your awesome help, DaveC426913 and atyy!- BandGeek13
- Post #5
- Forum: Introductory Physics Homework Help
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Understanding the Physics of Music: Frequencies, Overtones, and Resonance
Okay. But it is periodic, right?- BandGeek13
- Post #3
- Forum: Introductory Physics Homework Help
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Understanding the Physics of Music: Frequencies, Overtones, and Resonance
I just want to make sure I know these things correctly for an upcoming test, so if anyone can let me know, correct me (especially on the bolded stuff), or give me some extra info, that'd be great! -Music has a constant waveform (sinusoidal), meaning it consists of musical notes with constant...- BandGeek13
- Thread
- Basic physics Music Physics
- Replies: 6
- Forum: Introductory Physics Homework Help
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Gravitational Acceleration Problem
Alright. Thank you!- BandGeek13
- Post #6
- Forum: Introductory Physics Homework Help
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Gravitational Acceleration Problem
wait! instead of: 69 N [up] = (95 kg)(a) 0.73 m/s^2 = a is it: 1931 N [up] = (95 kg)(a) 20. m/s^2 = a- BandGeek13
- Post #4
- Forum: Introductory Physics Homework Help
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Gravitational Acceleration Problem
So would it be: F(normal)-F(gravity)=ma F(normal) - mg=ma 1000 N [up] - (95 kg)(9.8 N/kg [down])=(95 kg)(a) 1000 N [up] - 931 N [down] = (95 kg)(a) 69 N [up] = (95 kg)(a) 0.73 m/s^2 = a This seems very low..- BandGeek13
- Post #3
- Forum: Introductory Physics Homework Help
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Gravitational Acceleration Problem
Homework Statement A 95 kg man jumps, therefore exerting a force of 1000 N on a bathroom scale. The scale is in a motionless elevator in Earth's gravity. What is the man's acceleration? Homework Equations Newton's 2nd Law: F=ma Possibly Fg=mg ? The Attempt at a Solution I tried...- BandGeek13
- Thread
- Acceleration Gravitational Gravitational acceleration
- Replies: 5
- Forum: Introductory Physics Homework Help