Recent content by bboycs

then can you show me the step to get the final speed??

is that have to include mg??

final speed ?? A 5 kg vase is lifted vertically from rest to a distance of 10 m with a constant upward applied force of 60.0 N. Calculate iii) the final speed of the vase F=ma 60=5(a) a=12 v^2 = U^2+2as v^2=0+2(12)(10) V^2 = 240 v= 15.49m/s is the step correct~...

thanks for explaning~

this is for question (ii)... so the w is greater then tension?? another one is the question (i) is the tension = weight of elevator?? due to the acceleration is 0

i) the accelaration = 0 from equation T-W = ma so when a = 0 T-W =0 W = T the tension not equal to W ?? ii)moving downward...

a) An elevator travels upward at a constant speed. The elevator is hung by a single cable. Friction and air resistance are negligible. ii) Is the tension in the cable greater than, less than, or equal to the weight of the elevator? Explain. iii) The elevator travels...