Calculating Final Speed of a 5kg Vase

[bboycs]

final speed ??

A 5 kg vase is lifted vertically from rest to a distance of 10 m with a constant upward applied force of 60.0 N. Calculate

iii) the final speed of the vase

F=ma
60=5(a)
a=12

v^2 = U^2+2as
v^2=0+2(12)(10)
V^2 = 240
v= 15.49m/s

is the step correct~??

thanks for reply~

 

[method_man]

F=ma
60=5(a)
a=12

What about mg?

 

[bboycs]

is that have to include mg??

 

[method_man]

is that have to include mg??

Yes. You have three forces acting on a vase: F, mg & ma.

 

[bboycs]

Yes. You have three forces acting on a vase: F, mg & ma.

then can you show me the step to get the final speed??