Recent content by bchq333

d=1/2*v*t d=1/2*10*3521 d=17605.65 metres Is that correct?

Average velocity = displacement/time. Wouldn't the displacement be the same as the distance, as it is only traveling in a straight line? therefore yielding the same answer? Is there another way I can work out distance from what I have? Is what I have for time even correct? 3521 seconds or 58.6...

d is the initial velocity times stopping time

< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >[/color] A 50,000kg locomotive is traveling at 10m/s on a level track when the engines and brakes both fail. If there is a frictional force of 142N acting to slow it down, how far will it roll...