Recent content by beachy6

O i got it, so it would be +3pC

So How do i use this value to now find the charge on the inner surface?

ya, E=3pC/ (8.854x10^-12)(4pi (.012^2))= 4.68x10^13 N/pC

The electric field= 3pC/(ε0*SA)

Oops I am Sorry, I was looking at the picture wrong.What I meat to say is use the 3pC from the center charge and plug that into the equation and get 4.68x10^13 N/pC

When I use that Equation and use 7 as my charge I get the Electric field i get 1.09226 x 10^14 pC/N. But if I use 0, the obviously the electric field would be zero, but i don't think it can be zero since it is not in the conductor

Sorry my teacher did not explain this well at all, and expects us to know things that he doesn't discuss in class. thanks for helping i appreciate it!

A positive charge. So if we have a positive charge would the answer to #1 just be a +7pC?

repulsed

Ya i have asked several of my friends who have taken this class for help but they all could not remember exactly how to do a problem like this. My professor has really bad office hours and is not too helpful... thanks tho for the advice

Since it is in the inner surface it would be a negative because the formula is -q/4pir^2Once i find the electric field, how do i use this to find the charge? we have tried E*Area=Q/E0

This problem is so frustrating! I have tried everything possible i feel like. Anyone know if for numbers 7 and 9 we have to take into account the conuctors and subtract the radius by the width of the conductor?

So for number one when it asks "What is the charge on the inner surface of the smaller spherical conducting shell, 1.2 cm from the −3 pC point charge? would i use the equation q=(electric field)(surface area)(E0) but how do i fiend the electric field?

Electric field would be equal to the point charge/ (surface area)(ε0) correct?

Would you do take the area and multiply it by the charge? so (pi)(r^2)(-3pC)?