Recent content by Besh

I found chem pretty boring and that's about the only knowledge I've used in physics so far so I wouldn't worry about not having done it.

WOW great answer it seems perfectly logical. Thanks

well with the information given Aluminium: M = 27.0gm/mol = 0.027kg/mol ro = 2.7 x10^3 kg/m3 N_a = 6.02 x10^23 (atoms)/mol (it doesn't tell you the atoms part but I think that might jus be seen as common sense if you did chem at a level) first I calculated the mass of the Al atoms by...

I see what you mean. Tipler isn't being overly helpful but it kind of suggests the material being ohmic like you have suggested but what I am not sure about is whether the answer could be (d) or (e)?? How have you found the ret of this paper and the others?

iii) b - [zero potential] iv) d - [2.3 x 10^29] v) c - [other forces] Kind Regards, Billy [Hi Billy I guess your at the uni of leicester as I have the exact same questions to do. I've got these answers so far i) a ii) a iii) a iv) c (1.8x10^29) - I got a different answer for...