Recent content by betsinda

Thank you !

I think I have found b 180 = 250 - ae^-40b 150 = 250 - ae^-30b -70 = -ae^-40b 70/e^-40b = a -100 = -70/e^-40b * e^-30b 100/70 = e^40b * e ^-30b 10/7 = e^10b ln 10/7 = 10 b b = ln(10/7)/10 but how do I find a?

Homework Statement A yam is pust in an oven maintained at a constant temp of 250degrees C. Suppose that after 30 min the temp of the yam is 150degrees C and is increasing at a rate of 3degrees C/min. If the temp of the yam t minutes after it is put in the oven is modeled by...

Homework Statement The postion of a particle is given by s=2t^2-9t^2 where t is in seconds and s in meters a) when is the particle speeding up/slowing down Homework Equations The Attempt at a Solution I have calculated the 1st derivative (velocity) as 6t^2-18t 2nd...

B) is f differentiable at x = (1/2) explain So I could say that function is not differentiable at x=1/2 as the function is not not continuous? Sorry for being a little slow I'm just trying to wrap my head around the concept. Thanks

based on the fact that well every function is not differentiable, very function that is differentiable is continous. Or am I misunderstanding the concept?

would it then be correct to say that x=1/2 is not differentiable as it is not continuous at that point?

I would say that the graph is not continuous at x=1/2 as that point does not connect to any other point on the graph.

okay, I have fixed the graph. I have a line going from (1/2, 1) (1,1)(2,1) ect and a line going from (1/2,-1)(0,-1)(1,-1) ect, and a point at (1/2,0). How do i determine if this is continuous at 1/2?

sorry it continues to the right at -1

the line from the left approaches (1/2) at +1 and restarts at (1/2) at -1. There is a single point at (0,1/2)

Homework Statement F f(x)={(2x-1)/Absolute value(2x-1) x cannot equal (1/2) { 0 x = (1/2) a) is f continuous at X = (1/2) explain b) is f differentiable at x = (1/2) explain Homework Equations I have made the graph and x is a point...