ok i started again with this:
I drew a diagram as suggested. We are starting off in the Y direction at 210ms^-1
so Yold= 210ms^-1 Ynew=210cos(14)=204ms^-1
Xold=0 Xnew=210sin(14)=50.80ms^-1
then magnitude = (sqrt) 204^2 + 50.80^2 =210ms^-1 ? same as what we started with...
please...
ok tried this but got an even bigger answer...
Xold= 210ms^-1 Xnew= 0
Yold= 0 Ynew=210sin(14)=50.80
then I devided by 1.2 for each so: 210/1.2 and 50.80/1.2 then stuck those figures in the magnitude equation to get 180ms^-2
Homework Statement
An aircraft in level flight at a speed 210ms^-1 and traveling due north turns 14 degrees east. If the manoeuvre takes 1.2s to complete what are the magnitude and direction of the acceleration?
Homework Equations
a = v/t
magnitude = (sqrt)x^2 +y^2
The...