Recent content by bex4321

ok i started again with this: I drew a diagram as suggested. We are starting off in the Y direction at 210ms^-1 so Yold= 210ms^-1 Ynew=210cos(14)=204ms^-1 Xold=0 Xnew=210sin(14)=50.80ms^-1 then magnitude = (sqrt) 204^2 + 50.80^2 =210ms^-1 ? same as what we started with... please...

how do I know/workout what Xnew is?

ok tried this but got an even bigger answer... Xold= 210ms^-1 Xnew= 0 Yold= 0 Ynew=210sin(14)=50.80 then I devided by 1.2 for each so: 210/1.2 and 50.80/1.2 then stuck those figures in the magnitude equation to get 180ms^-2

Homework Statement An aircraft in level flight at a speed 210ms^-1 and traveling due north turns 14 degrees east. If the manoeuvre takes 1.2s to complete what are the magnitude and direction of the acceleration? Homework Equations a = v/t magnitude = (sqrt)x^2 +y^2 The...