Recent content by Bg5528

ok thanks for the help

Ok i understand that you will loose Surface area when you make cuts. Still confused though

Ok so say we want to maximize w from that equation: we would have to use the chain rule as well as the quotient rule?

Kinda. So i got to use S(l,h,w)= 2(hw)+2(hl)+(lw)=400 and V=lwh?

This may be irelevant but i went and set the surface area of the sheet to the surface area of the box with no lid. 400=2hw+2hl+lw => 400-wl=h(2w+2l) => (400-wl)/(2w+2l)=h

?? ok I am confused wouldn't that be Area if 20in * 20in?, so the surface area of the sheet of cardboard is 400 in^2?. Then the surface area of the box with no lid would be: SA= 2(hw)+2(hl)+(lw)?

I need help with this problem please. Finding the max volume of a box with an open lid. Using a 20 in by 20 inch sheet of cardboard and cutting out the corners. Equations i been using: Volume: Length*Width*height Area: L*W Perimeter: 2L+2W Can someone help me get started