I thought this as well - obtaining the graph of the inverse function would seem to be more within the scope of a first-week Pre-Calculus course - but it seems that the function itself is what is required.
Greetings all. I was solicited by a friend to find the inverse of a particular function, and I can't for the life of me determine/remember how.
The original equation is
y = 3+x^2+tan((1/2)*Pi*x)
with x on (-1,1).
The function is invertible - f' is always > 0 on that interval - but I have...