Recent content by Bilk

Well sir I thank you for your help. Even though my rough math and common sense told me this would work, your confirmation makes me feel much better about this design. Again thank you for taking the time to respond and best of everything to you!

I see a similar question was posed before. Link That scenario took into account the height of all the components above the fulcrum (where the front legs meet the floor). However they were looking at lateral force exerted on the tank and structure. Does that change anything?

Yes I see what you mean.

The sump weight is approx. 32lbs.

Ok thank you very much. My reasoning behind thinking the height of the sump would matter was in terms of the masses vertical distance above the pivot point acting as a moment arm or lever. The closer to the floor the shorter the lever, the higher, the longer the lever. I guess that...

No the water is seawater. It has an approximate weight of 8.55lbs/gal. The volume of the tank to the overflow is 45gal, yielding a weight of 385lbs. The glass tank weight approximately 100lbs. The stand approximately 45lbs. Yes no movement or tipping is desired :)

Yes I wasn't clear with the dimensions. The tank footprint is 24" square and 20" high. The supporting stand has the same footprint and stands 37" high. The sump is 20" from front to back, 15" wide and 16" tall. Am I correct in thinking the center of mass for the tank sitting on the stand...

Im wondering, did I post this to the wrong forum?

I'm in the process of building a reef aquarium. It will have a movable sump which will slide out from under the tank. I would like to know if this will exceed the tipping force and cause the tank to fall over. Components: tank=100lbs 24"x24"x20" 45g salt water=385lbs stand=approx...