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Jack draws rings of rhombuses about a common centre point. All rhombuses have the same side length. Rhombuses in the first, or inner, ring are all identical. Each rhombus has a vertex at the centre and each of its sides that meet at the centre is shared with another rhombus. They all have the...

In the Gadsden Diving Championships there is a panel of three judges. There are 12 scorecards with the numbers 1-12 on them, which are distributed so that each judge has four. After the diver has performed their routine, the judges each hold up a score card, and the diver's score is the sum of...

Thank you, however how can you do it with question d)? And what if, for the 3*3 castle, I only protected the outer boundary?

Yes, however AGT is for simple polygons, and the eyesight of the guard can stretch indefinitely. My polygon is irregular, and the laser is limited to the length of one tower

Well, I, as the King of the World, have built the great Tower of Me! However, because everyone seems to hate me for some reason, citizens keep trying to enter my tower to kill me. So, I have assigned some laser transmitters in my castle. However, as the technology is new, a laser transmitter can...

I'm assuming that after he gets to or passes 0, he does 54-hops again although I'm not certain. However, if you can, can you do both please?

If anyone can help me with my other questions, please do. Thanks ;)

Re: Year 7 & 8 mathematics puzzle This is my solution: - - - Updated - - - Also, sorry about the coding problem. I can't manage to only make the code into italics. If anyone can edit it, please do

This will be fairly easy to do, even in the eyes of a Year 7 Find x when $$\left({1-\frac{1}{2}}\right)\left({1-\frac{1}{3}}\right)...\left({1-\frac{1}{2017}}\right)=x$$ Remember: Year 7 and 8 maths only!

Can anyone help me with the following scenario: A hopping circuit is painted on a school playground. It consists of 25 small circles, with the numbers 0 ( at the 12 o' clock place) to 24, arranged as a big circle. Each student jumps either 3 or 4 spaces clockwise(so a student can end up either...

Divide 420 by 76 $$\frac{420}{76}\approx 5.5$$ So, multiply 0.6 with 5.5 $$0.6\cdot 5.5= 3.3$$ So side b is 3.3 mm

The maximum number of pizza pieces formula is: $$\frac{c(c+1)}{2} +1$$ where c is the number of cuts You'll also notice that; the maximum number of pieces formula -1 for every number = the triangle numbers So that's why we add a +1 at the end of the formula Substituting c for 6 gives...