How Does a Small Offset in Metal Pieces Increase with Distance?

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SUMMARY

The discussion focuses on calculating the increase in offset of two metal pieces bolted together, specifically when one piece is misaligned by 0.6mm. Using a fixed point and the principles of similar triangles, the offset grows proportionally with distance. When the distance from the fixed point increases from 76mm to 420mm, the offset increases to 3.3mm. This calculation is essential for ensuring proper alignment in mechanical assemblies.

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Hello all, sorry for the basic question but I suck at math and it's been many years since I had a course.

Anyway I've got two pieces of metal that bolt together and ideally are square and centered. However the pieces are not exactly square when bolted. The smaller piece is off by about .6mm. I need to know how big that mistake becomes further away from the center.

To put it into terms of a triangle where the first of two mounting holes is a point that is fixed: Side A is 76mm, side B (the second hole offset) is .6mm. So what would side B become if side A is now 420mm?

That's the first part of my question. Thanks!
 
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Divide 420 by 76

$$\frac{420}{76}\approx 5.5$$

So, multiply 0.6 with 5.5

$$0.6\cdot 5.5= 3.3$$

So side b is 3.3 mm
 

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