Recent content by bjbaldwi

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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    Thanks for all your help : )
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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    Fpush is equal to 0 and f net is equal to friction force so Fnet=Fpush+Ffriction Fpush=0 Fnet=Ffriction Ffriction=Fnet =(.6)mg---->.6*13*9.8=76.44 so Work=Fnet*D D = 1.2m/s*8.8s---->10.56 m so 76.44*10.56=807.2 J
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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    Fnet is equal to zero since the acc. is zero. F push is equal to friction force?
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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    the acceleration is zero because it is a constant velocity
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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    sorry its 13 kg 1.2 m/s and 8.8 s
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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    Steady speed says the friction is constant and friction force is kinetic friction*normal force or Fk*mg mg= normal force i think
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    Calc Push Force Req'd to Move 13g Steel Block on Steel Table

    How much work must you do to push a 13g block of steel across a steel table(coefficient of friction=.6) at a steady speed of 1.2 for 8.8 ? I know that Work=Force*Distance i know what the D is but i don't know how to calculate the force. i tried F=MA and got Fnet= Force pushed...