Recent content by bjbaldwi

Thanks for all your help : )

Fpush is equal to 0 and f net is equal to friction force so Fnet=Fpush+Ffriction Fpush=0 Fnet=Ffriction Ffriction=Fnet =(.6)mg---->.6*13*9.8=76.44 so Work=Fnet*D D = 1.2m/s*8.8s---->10.56 m so 76.44*10.56=807.2 J

Fnet is equal to zero since the acc. is zero. F push is equal to friction force?

the acceleration is zero because it is a constant velocity

sorry its 13 kg 1.2 m/s and 8.8 s

Steady speed says the friction is constant and friction force is kinetic friction*normal force or Fk*mg mg= normal force i think

How much work must you do to push a 13g block of steel across a steel table(coefficent of friction=.6) at a steady speed of 1.2 for 8.8 ? I know that Work=Force*Distance i know what the D is but i don't know how to calculate the force. i tried F=MA and got Fnet= Force pushed...