Recent content by Blanchdog95

THANK YOU SO MUCH! Now that I think about it the textbook did mention something about commutation; this probably saved me half a dozen points on my test next week.

I've attempted to solve this by separating A into a diagonal matrix D and nilpotent matrix N: D = {{1, 0}, {0, 0}} N = {{0, 0}, {1, 0}} e^(At) = e^((D + N)t) = e^(Dt) * e^(Nt) When N is raised to the second power, it becomes the zero matrix. Therefore, e^(Nt) = I + Nt = {{1, 0}, {t, 1}} Note...