Recent content by blazeatron

Hi ... I have not seen any H-bridge producing a pwm output switching between positive and negative voltages ... But u can feed that pwm signal to a LEVEL SHIFTER or CLAMPER circuit to shift its DC LEVEL appropriately to get both positive as well negative-going pulses , right ? Then , u can...

Ʃ (2^n)/(3^n) = Ʃ (2/3)^n = 2

Hi ... All the 3 systems are time - invariant ... The first two systems are non-linear

i think that you are talking about static friction and not about rolling friction...What really happens is that we are making the rear wheel(by applying force on the pedal) to push the ground backward and hence the ground will exert a frictional force on the rear wheel in the forward...

I think that you forgot to consider the fact that the bicycle pedal drives the rear wheel and not the front wheel:smile:

ya ... it is a non-linear time-invariant system

When we are speaking about uniform velocity ,it means that both magnitude and direction of the velocity VECTOR must be uniform with time . But when we say uniform motion , we usually refer to the magnitude alone , irrespective of the direction . So , Uniform motion need not have uniform velocity...

Hi ... i dono how to get the result a^p≡b^p mod p^2 using Fermat's theorem . But , the result can be proven using Binomial series. Let a = mp + r , b = np + r where m and n are arbitrary integers.r is also an integer that denotes the remainder when a or b is divided by p.It is clear that our...

Hi... For the given conditions ,the function g need not be continuous. Example : f(x) = sin(x) - 3 , h(x) = sin(x) + 3 , g(x) = sin(1/x) for this example , f(x) < g(x) < h(x) . f and h are continuous . But g is not continuous at x tends to 0. Instead of g(x) = sin(1/x) , u can also take a...

Hi...The formula that u had provided in your post will give you only the magnitude of the FORCE vector... To get the direction of the resultant force, you must find the unit vector that represent the line joining the two charges... In this case , it is (3i - 2j)/√(9 + 4) = (3/√13)i - (2/√13)j...

To start , Forget about f(2x) for a while... f(x) = 3 implies that irrespective of what values the variable 'x' can take, the function value is 3 only... so , f(x) = 3 is a constant function for all values of x...The set of values takne by '2x' is actually a subset of values taken by 'x'...