Recent content by bmannaa

Yes it does in the formula n^2 - 2 (n - 1) +...+ n^2 = (n-1)^3 + n^3 1) 1=1 put n = 1 2) 2 + 3 + 4 = 1 + 8 put n = 2 3) 5 + 6 + 7 + 8 + 9 = 8 + 27 put n = 3 4) 10 + 11 + 12 + 13 + 14 + 15 + 16 = 27 + 64 put n = 4 Yep! I didn't get to prove it by induction.

I guess the conjecture is n^2 - 2 (n - 1) +...+ n^2 = (n-1)^3 + n^3 and it holds by trivial processing of the two sides