Recent content by Bob jefferson

so i need a bit of guidance, would ##sin^2(10t+\frac \pi 4)## equal to ##\frac 1 2(1-cos(2*10t+\frac \pi 4))##

so would it be some thing like ##\frac 1 R \int_0^{0.5} V^2(t) dt ##

Oh so actually putting V^2/r in the integral.

so i just multiply 0.5s with the value i obtained from the integration.

I think the answer should be in joules as its asking for energy dissipated.

No

I integrated this V(t) = 6sin(10t+pi/4)*exp(-2t)

Homework Statement A resistor of resistance 10Kohms has voltage across it described by the function V(t) = 6sin(10t+pi/4)*exp(-2t) Volts Calculate the energy dissipated in the resistor between t=0 and t=0.5 Homework EquationsThe Attempt at a Solution I have done the definite integral and have...