Recent content by Bob Spoongfield

Try the Phillip Harris website and Rapid Electronics... they are both suppliers for schools

Yer I think that they just want us to think complicated, but actually realize that it is something a lot simpler. I am just going to use current against wavelength and resistance against wavelength and see which one looks more like the one it should

I have just spoken to my Teacher. He said that we are on the right lines, except that we needt o measure the light intensity, not the LDR intensity ( :confused: ) He also said about using the resistance ... the Resistance is inversely proportional to the Light Intensity. That's all the info he...

unlucky. Mine's A-level plan and is in for the 15th so I have a bit of time to get it right, but I will definitely post back to you all asap.

Yer, I'm hoping to use that as well. I will be checking with my teacher tomorrow! see what he says. I was looking at the formula for intensity as well and it seems much too complicated for this level so I guess there must be some simpler way. will post back tomorrow with more info. lte's hope...

Hi, I am also doing this scenario and investigation. I was just reading the reast of the threads and noticed that a lot of people have suggested using the current for intensity, however, I do believe that one of the graphs we need to present/example is Intensity against resistance, or in our...