Recent content by BobbyFluffyPric
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Graduate Is a Second Order Symmetric Tensor Always Represented by a Symmetric Matrix?
Guys, thanks for all the insight, but I'll need a little time to digest this stuff! I don't want to start asking questions off the cuff!- BobbyFluffyPric
- Post #11
- Forum: Differential Geometry
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Graduate Is a Second Order Symmetric Tensor Always Represented by a Symmetric Matrix?
Explain, I wonder if you can recommend me some text that explains this in detail, although I suppose that as an engineering student I shall have little need to delve further into it. However, I am curious as to this distinction between contravariant and covariant vectors (I actually read in some...- BobbyFluffyPric
- Post #8
- Forum: Differential Geometry
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Graduate Is a Second Order Symmetric Tensor Always Represented by a Symmetric Matrix?
Thanks Explain, thank you, I'm more assured now :smile: , even though I don't understand the thing about thinking of "contravariant vectors and covariant vectors as things coming from two different vector spaces" :confused: - as far as I know, a vector is a vector, and one can only talk of...- BobbyFluffyPric
- Post #6
- Forum: Differential Geometry
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Graduate Is a Second Order Symmetric Tensor Always Represented by a Symmetric Matrix?
Okay, simpler: you said that B[SIZE="1"]uv=B(e[SIZE="1"]u,e[SIZE="1"]v). So it's what I said before, if B[SIZE="1"]u[SIZE="1"]v= B(e[SIZE="1"]u,E[SIZE="1"]v), where the underscore under the subscript indicates that it is a superscript, and E[SIZE="1"]i are the covariant basis vectors...- BobbyFluffyPric
- Post #4
- Forum: Differential Geometry
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Graduate Is a Second Order Symmetric Tensor Always Represented by a Symmetric Matrix?
I was hoping you'd say no! Explain, thanks for your post - however, I was hoping you'd say the contrary, as I seem to have come to a conclusion of sorts of why the matrix of a second order tensor is not necessarily symmetric. I'll try and explain my reasoning: From what I believe, a second...- BobbyFluffyPric
- Post #3
- Forum: Differential Geometry
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Graduate Is a Second Order Symmetric Tensor Always Represented by a Symmetric Matrix?
Is the matrix of a second order symmetric tensor always symmetric (ie. expressed in any coordinate system, and in any basis of the coordinate system)? Please help! :blushing: ~Bee- BobbyFluffyPric
- Thread
- Matrices Symmetric Tensors
- Replies: 10
- Forum: Differential Geometry
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Undergrad Vector or Not Vector: Analysis of Magnitude & Direction
HallsofIvy, as far as I had gathered, if the quantities a[SIZE="1"]i transform, under a general transformation of the coordinate system x’[SIZE="1"]i=f(x[SIZE="1"]1,x[SIZE="1"]2,x[SIZE="1"]3) (where f can be nonlinear), as a’[SIZE="1"]i=(δx’[SIZE="1"]i/δx[SIZE="1"]j)a[SIZE="1"]j, then they are...- BobbyFluffyPric
- Post #16
- Forum: Differential Geometry
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Undergrad Vector or Not Vector: Analysis of Magnitude & Direction
I want to thank all of you for taking time to help out with your views. I’ll try and draw some conclusions. HallsofIvy, thank you so much for your reply, it is much appreciated. Yes, I think I understood everything you said, but perhaps I didn't express myself too well concerning the...- BobbyFluffyPric
- Post #14
- Forum: Differential Geometry
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Undergrad Vector or Not Vector: Analysis of Magnitude & Direction
If a vector is simply "any quantity having magnitude and direction", then how can a vector's components NOT transform according to the rule of transformation for the components of a vector when we apply a transformation of the coordinate system? Or alternatively, given three numbers (for the 3D...- BobbyFluffyPric
- Thread
- Vector
- Replies: 42
- Forum: Differential Geometry