It looks to me like the 16 Ohm and 34 Ohm resistors are in parallel. Is that correct? Does this mean that the 16 Ohm and 34 Ohm resistors each have 2.426V across them?
P=RI2=V2/R
Assuming this is the correct equation, I know R (34 Ohms) but that's it, right? I don't know current or voltage (the only voltage I know is what's left over). How can I separate that to find what I need for the 34 Ohm resistor?
The current through the 25 Ohm resistor is .222965A. This means the voltage across the resistor is 5.574V. This leaves 2.426V unaccounted for. How do I know how much power is dissipated from the rightmost resistor?
I don't really know what you mean. Isn't voltage equal across a parallel circuit? I also don't know what you mean by two series resistors...Is this circuit a series (with the 16 and 25 Ohm) with a parallel circuit (34 Ohm)? Or a parallel (16 and 34) with one in series (25 Ohm)? I have tried...
Ok, I guess I need to clarify my work. Here is what I have so far...
Rtotal=35.88
I=8/35.88=.222965
P=E2/R
P=82/34
P=1.8823W
The part that confuses me is the combination circuit part, and I am not sure how that plays into the power dissipation of the resistor...
Homework Statement
What is the power dissipated in the 34-Ohm resistor?
Homework Equations
P=RI^2
The Attempt at a Solution
I have found the total current in the system as well as the current through the resistor, and keep getting 1.88, which is incorrect. Any suggestions on...