Recent content by bolzano95

On the exam - ultimately no.

Yes, checked every solution. If I couldn't solve the problem on my own, I tried to learn from the solution code and if I had additional questions - wrote my problem on stack exchange. That's why I'm so flabbergasted why I failed.

Hi PeroK, I took a break for 1year from uni and changed my degree to management. Finished bachelors degree and currently doing masters in Business Informatics. If you need more info, please send me a pm :)

We got only 1 exam = Final exam. Failed this one. I went to the professor and explained my problem. He just looked at me and said nicely " You have to solve this on your own."

Hi everyone, Hopefully I'm writing this in the correct part of PhysicsForum. Here is my problem: I'm really struggling with my programming class (basics of python3 - loops, dictionaries, numpy). What I did this semester: 1. Participated in every class 2. Solved everything our course offered...

Hi! I recently noticed I have really big problems concentrating when attending my college lectures (1year). Let me give an example: I come to the physics lecture and I'm totally engaged in the lecture material. But after 20min I start to lose interest and I have to physically force myself to...

I checked the torque and I agree there is something wrong, but unfortunately I have to use the given formula (it's mandatory). But I think that in the coefficient C are hidden necessary units. I suppose that the goal of this problem is to write a homogeneous linear differential formula, but...

Sorry, I meant the rope does not slip on the pulley. I fixed the last equations and double checked the R-s. But I'm still confused by what you mean with Torque = moment of inertia times ... what? The torque in this case is given as a product of C and angular velocity, where C is a factor of...

Oh yes, the initial conditions and parameters of the system given. So there is no chance of solving this analytically, only numerically?

There is an mass-spring oscillator made of a spring with stiffness k and a block of mass m. The block is affected by a friction given by the equation: $$F_f = -k_f N tanh(\frac{v}{v_c})$$ ##k_f## - friction coefficient N - normal force ##v_c## - velocity tolerance. At the time ##t=0s##...

I meant this example: The correct solution here as well is the dark blue N, because all forces have to cancel out in the diagram. I was confused because there was a mistake in solution manual and I wanted to be sure if I understand the normal force acting on the rod.

I knew it guys! The solution in the 2nd image is wrong! Got it now. Thank you for your help.

Yes, then it's quite simple. But what about if the rod is directed downwards as the picture is shown above?

Yes, the rod is hinged at point A. If there were no hinge and the friction coefficient would be low, then I would conclude that the only force of a wall acting on a rod is perpendicular to a wall ------> blue N. But this example poses a doubt: the situation is almost similar, only in this case...