Recent content by Borvorn
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1 maximal subgroup -> prime order
I know that this post is old, but since it is top result when i google this problem, I think it would be good if i give further detail of solution. Let $a \in G \setminus M$. Then $a$ generate $G$ which mean $G$ is cyclic. Suppose $|G| = p_{1}^{r_{1}}...p_{n}^{r_{n}}$ where $p_{i}$ is prime. So...- Borvorn
- Post #4
- Forum: Calculus and Beyond Homework Help